B

a

Una dimostrazione  '' tutta triangolare ''  del teorema di Pitagora

 \frac{ a }{b}   \;  = \;  \frac{ p }{a}  \;  = \;  \frac{ d }{c}  \; =  \;  r

T_c  =  T_a  +  T_b

c d  =  a p  +  b a 

c c r  =  a a r  +  b b r

c ²  =  a ²  +  b ²

d

d

muovi = (3.4436754686555116, 2.196452328159644)
B = If(x(muovi) > 0.0 ∧ y(muovi) > 0.0, muovi)
a_1 = Line(B, yAxis)
C = Intersect(a_1, xAxis)
A = (0, 0)
c = Segment(B, A)
b = Segment(A, C)
a = Segment(C, B)
d_2 = OrthogonalLine(B, c)
D = Intersect(d_2, xAxis)
e = Segment(C, D)
f = Segment(B, D)
D' = Mirror(D, B)
g = Segment(B, D')
h = Segment(D', A)
poli1, b_1, a_2, c_1 = Polygon(A, C, B)
B' = Mirror(B, C)
i = Segment(A, B')
j = Segment(C, B')
T_c, d', a_3, b_2 = Polygon(A, B, D')
T_a, d_1, p, d = Polygon(B, C, D)
T_b, b', a_4, c_3 = Polygon(A, C, B')
α = Angle(B, C, A)
β = Angle(A, B, D)
E = Midpoint(muovi, D')
F = Midpoint(C, B')